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sync: implement simple pooling in sync.Pool
This commit is contained in:
committed by
Ron Evans
parent
9e34ca9e5f
commit
29f8d22a2d
+9
-3
@@ -1,13 +1,18 @@
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package sync
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// Pool is a very simple implementation of sync.Pool. It does not actually
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// implement a pool.
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// Pool is a very simple implementation of sync.Pool.
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type Pool struct {
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New func() interface{}
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New func() interface{}
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items []interface{}
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}
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// Get returns the value of calling Pool.New().
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func (p *Pool) Get() interface{} {
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if len(p.items) > 0 {
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x := p.items[len(p.items)-1]
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p.items = p.items[:len(p.items)-1]
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return x
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}
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if p.New == nil {
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return nil
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}
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@@ -16,4 +21,5 @@ func (p *Pool) Get() interface{} {
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// Put drops the value put into the pool.
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func (p *Pool) Put(x interface{}) {
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p.items = append(p.items, x)
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}
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@@ -0,0 +1,50 @@
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package sync_test
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import (
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"sync"
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"testing"
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)
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type testItem struct {
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val int
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}
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func TestPool(t *testing.T) {
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p := sync.Pool{
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New: func() interface{} {
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return &testItem{}
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},
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}
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i1P := p.Get()
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if i1P == nil {
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t.Error("pool with New returned nil")
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}
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i1 := i1P.(*testItem)
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if got, want := i1.val, 0; got != want {
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t.Errorf("empty pool item value: got %v, want %v", got, want)
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}
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i1.val = 1
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i2 := p.Get().(*testItem)
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if got, want := i2.val, 0; got != want {
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t.Errorf("empty pool item value: got %v, want %v", got, want)
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}
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i2.val = 2
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p.Put(i1)
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i3 := p.Get().(*testItem)
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if got, want := i3.val, 1; got != want {
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t.Errorf("pool with item value: got %v, want %v", got, want)
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}
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}
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func TestPool_noNew(t *testing.T) {
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p := sync.Pool{}
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i1 := p.Get()
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if i1 != nil {
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t.Errorf("pool without New returned %v, want nil", i1)
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}
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}
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