Files
tinygo/src/examples/echo/echo.go
T
Ayke van Laethem b67351babe machine: define Serial as the default output
Previously, the machine.UART0 object had two meanings:

  - it was the first UART on the chip
  - it was the default output for println

These two meanings conflict, and resulted in workarounds like:

  - Defining UART0 to refer to the USB-CDC interface (atsamd21,
    atsamd51, nrf52840), even though that clearly isn't an UART.
  - Defining NRF_UART0 to avoid a conflict with UART0 (which was
    redefined as a USB-CDC interface).
  - Defining aliases like UART0 = UART1, which refer to the same
    hardware peripheral (stm32).

This commit changes this to use a new machine.Serial object for the
default serial port. It might refer to the first or second UART
depending on the board, or even to the USB-CDC interface. Also, UART0
now really refers to the first UART on the chip, no longer to a USB-CDC
interface.

The changes in the runtime package are all just search+replace. The
changes in the machine package are a mixture of search+replace and
manual modifications.

This commit does not affect binary size, in fact it doesn't affect the
resulting binary at all.
2021-05-13 16:43:37 +02:00

45 lines
914 B
Go

// This is a echo console running on the device UART.
// Connect using default baudrate for this hardware, 8-N-1 with your terminal program.
package main
import (
"machine"
"time"
)
// change these to test a different UART or pins if available
var (
uart = machine.Serial
tx = machine.UART_TX_PIN
rx = machine.UART_RX_PIN
)
func main() {
uart.Configure(machine.UARTConfig{TX: tx, RX: rx})
uart.Write([]byte("Echo console enabled. Type something then press enter:\r\n"))
input := make([]byte, 64)
i := 0
for {
if uart.Buffered() > 0 {
data, _ := uart.ReadByte()
switch data {
case 13:
// return key
uart.Write([]byte("\r\n"))
uart.Write([]byte("You typed: "))
uart.Write(input[:i])
uart.Write([]byte("\r\n"))
i = 0
default:
// just echo the character
uart.WriteByte(data)
input[i] = data
i++
}
}
time.Sleep(10 * time.Millisecond)
}
}