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runtime: don't call sleepTicks with a negative duration
There are rare cases where this can happen, see for example https://github.com/tinygo-org/tinygo/issues/4568
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@@ -230,13 +230,15 @@ func scheduler(returnAtDeadlock bool) {
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println("--- timer waiting:", tim, tim.whenTicks())
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}
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}
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sleepTicks(timeLeft)
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if asyncScheduler {
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// The sleepTicks function above only sets a timeout at which
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// point the scheduler will be called again. It does not really
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// sleep. So instead of sleeping, we return and expect to be
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// called again.
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break
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if timeLeft > 0 {
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sleepTicks(timeLeft)
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if asyncScheduler {
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// The sleepTicks function above only sets a timeout at
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// which point the scheduler will be called again. It does
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// not really sleep. So instead of sleeping, we return and
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// expect to be called again.
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break
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}
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}
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continue
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}
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