make interp timeout configurable from command line

This commit is contained in:
Damian Gryski
2022-08-04 15:26:44 -07:00
committed by Ron Evans
parent a4ee98e0e1
commit 0b77e92c50
7 changed files with 34 additions and 28 deletions
+7 -5
View File
@@ -30,10 +30,11 @@ type runner struct {
objects []object // slice of objects in memory
globals map[llvm.Value]int // map from global to index in objects slice
start time.Time
timeout time.Duration
callsExecuted uint64
}
func newRunner(mod llvm.Module, debug bool) *runner {
func newRunner(mod llvm.Module, timeout time.Duration, debug bool) *runner {
r := runner{
mod: mod,
targetData: llvm.NewTargetData(mod.DataLayout()),
@@ -42,6 +43,7 @@ func newRunner(mod llvm.Module, debug bool) *runner {
objects: []object{{}},
globals: make(map[llvm.Value]int),
start: time.Now(),
timeout: timeout,
}
r.pointerSize = uint32(r.targetData.PointerSize())
r.i8ptrType = llvm.PointerType(mod.Context().Int8Type(), 0)
@@ -58,8 +60,8 @@ func (r *runner) dispose() {
// Run evaluates runtime.initAll function as much as possible at compile time.
// Set debug to true if it should print output while running.
func Run(mod llvm.Module, debug bool) error {
r := newRunner(mod, debug)
func Run(mod llvm.Module, timeout time.Duration, debug bool) error {
r := newRunner(mod, timeout, debug)
defer r.dispose()
initAll := mod.NamedFunction("runtime.initAll")
@@ -199,10 +201,10 @@ func Run(mod llvm.Module, debug bool) error {
// RunFunc evaluates a single package initializer at compile time.
// Set debug to true if it should print output while running.
func RunFunc(fn llvm.Value, debug bool) error {
func RunFunc(fn llvm.Value, timeout time.Duration, debug bool) error {
// Create and initialize *runner object.
mod := fn.GlobalParent()
r := newRunner(mod, debug)
r := newRunner(mod, timeout, debug)
defer r.dispose()
initName := fn.Name()
if !strings.HasSuffix(initName, ".init") {