switch router output to be a processor instead of specific output per route

This commit is contained in:
Joel Wetzell
2026-03-04 21:21:11 -06:00
parent 078e6ec68c
commit b7a8b04a72
28 changed files with 246 additions and 140 deletions

View File

@@ -0,0 +1,55 @@
package processor
import (
"context"
"errors"
"fmt"
"log/slog"
"github.com/jwetzell/showbridge-go/internal/common"
"github.com/jwetzell/showbridge-go/internal/config"
)
type RouterOutput struct {
config config.ProcessorConfig
ModuleId string
logger *slog.Logger
}
func (dl *RouterOutput) Process(ctx context.Context, payload any) (any, error) {
router, ok := ctx.Value(common.RouterContextKey).(common.RouteIO)
if !ok {
return nil, errors.New("router.output no router found")
}
err := router.HandleOutput(ctx, dl.ModuleId, payload)
if err != nil {
return nil, fmt.Errorf("router.output failed to send output: %w", err)
}
return payload, nil
}
func (dl *RouterOutput) Type() string {
return dl.config.Type
}
func init() {
RegisterProcessor(ProcessorRegistration{
Type: "router.output",
New: func(config config.ProcessorConfig) (Processor, error) {
params := config.Params
moduleId, err := params.GetString("module")
if err != nil {
return nil, fmt.Errorf("router.output module error: %w", err)
}
return &RouterOutput{config: config, ModuleId: moduleId, logger: slog.Default().With("component", "processor", "type", config.Type)}, nil
},
})
}